$date2 = ‘2010-06-20’;$date1 = ‘2010-06-24’;$days = (strtotime($date1) – strtotime($date2)) / (60 * 60 * 24);echo $days; some other ways are also there. can any one … days difference in phpRead more
$date2 = ‘2010-06-20’;$date1 = ‘2010-06-24’;$days = (strtotime($date1) – strtotime($date2)) / (60 * 60 * 24);echo $days; some other ways are also there. can any one … days difference in phpRead more